Question

64x⁴-81x⁴solve this ​

Answer 1

Answer:

64x^4-81x^4

=(8x^2)^2-(9x^2)^2

=(8x^2-9x^2)(8x^2+9x^2)

ANSWER=(8x^2-9x^2)(8x^2+9x^2)

Answer 2

Answer:

x = 0,0,0,0 are the posible values for x

Step-by-step explanation:

61x^4 - 81x^4 = 0

x^4(61-84) = 0

-23x^4 = 0

Here -23 = 0 is not possible so x^4 = 0

then x = 0,0,0,0 since x^4 is the fourth power of x so it must contain four roots