Question

64yto the power 4 + 8y cube)/4y3​

Answer 1

Answer:

$\frac{64 {y}^{4} + 8 {y}^{3} }{4 {y}^{3} } = \frac{64 {y}^{4} }{4 {y}^{3} } + \frac{8 {y}^{3} }{4 {y}^{3} } = 16y + 2$