Question

65. Ram starts his bike from rest and moves along a
straight path. If he attains a speed of 72 km h-1 in
10 s, determine his acceleration.​
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Answer 1

Given :

• Ram starts his Bike from rest and moves along a straight line
• Attains a speed of 72 km/h in 10 seconds

To Find :

• We have to find the acceleration of the Bike

Concept Used :

Newton gave 3 Mathematical Equations to describe the motion of an object with respect to the function of time

Newton Equation of Motion :

☞ $\boxed{\sf{v = u + at}}$

☞ $\boxed{\sf{s = ut + \dfrac{1}{2}at^2}}$

☞ $\boxed{\sf{v^2 = u^2 + 2as}}$

Where the given variable stands for

• u = Initial Velocity
• v = Final Velocity
• a = Acceleration of object
• t = Time Taken
• s = Displacement of object

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Solution :

We have been Given that

• Initial Velocity ( u ) = 0 m/s
• Time Taken = 10 s
• Final Velocity ( v ) = 72 km / h

Converting all given Quantities in SI unit

$\longrightarrow \sf{ v = 72 \: km/h = 72 \times \dfrac{5}{18}}$

$\longrightarrow \sf{ v = \cancel{72}\times \dfrac{5}{\cancel{18}}}$

$\longrightarrow \sf{ v = 4 \times 5}$

$\longrightarrow \sf{ v = 20 \: m/s}$

Final Velocity in SI unit is 20 m/s

Using First Equation of Motion :

$\longrightarrow \large{\underline{\boxed{\sf{\gray{v = u + at}}}}}$

Putting values in above Equation

$\longrightarrow \sf{20 = 0 + a \times 10}$

$\longrightarrow \sf{20 = 10a}$

$\longrightarrow \sf{a = \dfrac{20}{10}}$

$\longrightarrow \underline{\boxed{\sf{a = 2 \: m/s}}}$

Acceleration of Bike is 2 m/s

$\large{\underline{\boxed{\sf{\blue{Acceleration \: of \: Bike = 2 \: m/s}}}}}$

Answer 2

Acceleration Of Bike=2m/s

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