Question

65.
The accelaration of a particle of charge of 0.5 C
and 500 mg mass kept in an electric field of
intensity 200 N/C is
a) 2000 m/s
b) 200 m/s
c) 500 m/s2
d) 20 m/s2​

Answer 1

The accelaration of a particle of charge of 0.5 C. and 500 mg mass kept in an electric field of. intensity 200 N/C is. a) 2000 m/s.

Answer 2

Answer:

option (b)

Explanation:

for electric intensity we know the formula

E=f/q__1

given data: E=200,q=0.5C, m=500 to convert mass in SI unit therefore m=0.5kg

from 1 f=q×E

and also f=ma

f = 0.5×200

f = 100

f = ma

f/m = a

100/0.5 = a

200m/s^2= a

m/s^2 us it's unit