Question

[65] The arithmetic mean of the square of first 2n natural
numbers is:
a)
(a) 1/6 (2n + 1) (4n - 1)
(b) 1/6 (2n-1)(4n - 1)
(c) 1/6(2n-1)(4n + 1)
(d) 1/6(2n + 1) (4n+1)​

Answer 1

Answer:

your answer is b) plz mark me as brainlist

Answer 2

Answer:

Sum of squares of the first n natural numbers =6

n(n+1)(2n+1)

Their arithmetic mean is n Sum= 6nn(n+1)(2n+1)

= 6(n+1)(2n+1)

Hence, C is correct.

Step-by-step explanation:

hope this helps you