Question

65. The G.P. whose 3^( rd ) and 6^( th ) terms are 1, -1/8 respectively is​

Answer 1

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Step-by-step explanation:

ANSWER ::

Let a be 1st term and r be the common ratio

Then 3rd tem = a×r^2

6th tem = a×r^5

Now

a×r^2 = 1

a = 1/r^2

Also

a×r^5 = - 1/8

1/r^2×r^5 = - 1/8

r ^3 =-1/8

r = - 1/2

So

a = 4

So the GP is 4, - 2,1,-/2,1/4,-1/8,1/16,............