65. Through a rectangular field of the length 90m, and breadth 60m, two roads are ii constructed which are parallel to the sides and cut each other at right angles through the centre of the field. if the width of each road is 3m , find : i)the area covered by the roads ii)the cost of constructing the roads at rate of Rs 110m ^ 2 .
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Step-by-step explanation:
Solution 7:
Length of the road along the length of the field= 90m
Breadth= 3m
Area of the road= l\times bl×b
=90m\times3m=270m^2=90m×3m=270m
2
Similarly, the area of the road parallel to the breadth of the field= l\times bl×b
=60m\times3m=180m^2=60m×3m=180m
2
Area of the common portion= 3m\times3m=9m^23m×3m=9m
2
(i) Area of the two roads
=270m^2+180m^2-9m^2=270m
2
+180m
2
−9m
2
=450m^2-9m^2=441m^2=450m
2
−9m
2
=441m
2
(ii) Cost of constructing the roads
=Rs\ 110\times441=Rs\ 48,510=Rs 110×441=Rs 48,510
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