Question

65. What is the 7th term of a geometric sequence if the difference between its 3rd term and 1st term is 18 and that between its 4th and 2nd term is 9?
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Answer 1

Step-by-step explanation:

Let 1st term is a and common ratio is r

a(r² – 1) = 18

ar(r² – 1) = 9

=> r = 1/2

=> a = – 24 .

7 th term = (–24)(1/2)⁶ = –24/64 = –3/8