Physics, asked by soyetadey472, 6 months ago

6500J of heat energy is supplied to raise the temperature of 2.5kg of lead from 30degree Celsius to 50degree Celsius.Calculate the specific heat of lead?

Answers

Answered by mittu751

4

Answer:

130 J/Kg K

Explanation:

Specific heat =Q/m∆T

∆T= t2 -t1

=50 -30 is 20

now S is 6500/2.5 ×20=130 Joules per kg Kelvin

please mark as brainlest answer

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