Question

65g of glucose is dissolve in 435g of water.Calculate the concentration of solution.​

Answer 1

Answer:

13%

Explanation:

glucose=6 (solute)

water=435g (solvent)

w.t of solution=65+435=500g

(w/w)% = (amount of solute/amount of solution)×100%

65/500×100

65/5=13

hence the concentration of solution is 13%

HOPE IT'S HELPFUL

Answer 2

Answer:

Answer  in  two concentration terms  

1) molality(m)= 0.722m

2)% concentration=13%

Explanation:

We know that, molality= Moles  of solute / mass of solution in kg

so,  moles of solute =65/180        ….[molecular mass of  glucose=180]

and mass of solution in kg =435+65=500

                                                  =500/1000=  0.5kg

so molality =$\frac{65\frac{1}{180} }{0.5}$   = 0.722m

and  

By concentration =

Mass of solute in grams ÷ mass of solution in gram  ×100

SO,   concentration% =  $\frac{65}{500}$×100 %  

                                        =13%