Question

66+{10+15of3-(20+30-45÷5)}

Answer 1

These types of questions can be solved easily by applying $<b>BODMAS rule.</b>$


B = Bracket

O = of ( × )

D = Division

M = Multiplication

A = Addition

S = Subtraction



Given :

66 + { 10 + 15 of 3 - ( 20 + 30 - 45 ÷ 5 ) }

= 66 + { 10 + 15 × 3 - ( 20 + 30 - $<u>45 ÷ 5</u>$ ) }

= 66 + { 10 + 15 × 3 - ( $<u>20 + 30</u>$ - 9 ) }

= 66 + { 10 + 15 × 3 - ( $<u>50 - 9</u>$ ) }

= 66 + { 10 + $<u>15 × 3</u>$ - 41 }

= 66 + { $<u>10 + 45</u>$ - 41 }

= 66 + { $<u>55 - 41</u>$ }

= 66 + 14

= 80




Hence, $<u>the answer is</u>$ $<I><b><u> 80.</u></b></I>$