Question

66) Find the perimeter of a rectangle whose breadth is 9cm and diagonal is 41cm.
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Answer 1

Answer:

answer solved and attached in the attachment above

Step-by-step explanation:

hope it helps you...

Answer 2

[ REFER TO THE ATTACHMENT ]

Here, is a rectangle ABCD in witch breadth and diagonal are given

• AB breadth = 9cm
• AC diagonal = 41cm

As we know that

All angles of a rectangle are right angles i.e. 90°

So,

AC² = AB² + BC² [ Pythagoras theorem ]

Now,

→ AC² = AB² + BC²

→ (41)² = (9)² + BC²

→ BC² = (41)² - (9)²

→ BC² = 1681 - 81

→ BC² = 1600

→ BC = √1600

→ BC = 40cm

Therefore length of the rectangle BC = 40cm

As we know that

Perimeter of a rectangle = 2 (l + b)

Put the values in the formula

Now,

→ Perimeter of the rectangle = 2 (l + b)

→ Perimeter of the rectangle = 2 (40 + 9)

→ Perimeter of the rectangle = 2 × 49

→ Perimeter of the rectangle = 98cm

Hence, the perimeter of the rectangle is 98cm.