Math, asked by abuzarsaifi217, 1 year ago

66. (sec A + tan A - 1) (sec A- tan A + 1) = 2 tan A

Answers

Answered by av1266108

2

$answer$

[secA+(tanA-1)(secA-(tanA-1)]

=sec²A-(tanA-1)²

=1/cos²A-(tan²A-2tanA+1)

=1+tan²A-tan²A+2tanA-1

=(1-1)tan²A-tan²A + 2tanA

=0+0+2tanA

=2tanA=2tanA

hence verified!

Answered by ranaabhi1103

0

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