English, asked by ifrahzameer2399, 10 months ago

66. The sum of all integers between 200 and 800, which is divisible by 9, is
(A) 32796
(B) 32976
(C) 32967
(D) 32769

Answers

Answered by sarthakk696944
5

Answer:

(c) 32967

By mistakely

Answered by dk6060805
2

Answer:

(C) 32967

Explanation:

The numbers lying between 200 and 800, which are divisible by 9 are,

207, 216, 225, .... 792

Here, First term is, a = 207

and Last term is = 792

difference is, d = 9

Let the total number of terms of the A.P. is equal to n.

and we know the formula of A.P. series

last term = a + (n - 1) d

792 = 207 + (n - 1) 9

9 (n - 1) = 585

9n = 594

n = 66

Sum of 66  = 66 / 2 (207 + 792)

= 33(999)

= 32967

Thus, the required sum is 32967.

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