English, asked by ifrahzameer2399, 1 year ago

66. The sum of all integers between 200 and 800, which is divisible by 9, is
(A) 32796
(B) 32976
(C) 32967
(D) 32769

Answers

Answered by sarthakk696944
5

Answer:

(c) 32967

By mistakely

Answered by dk6060805
2

Answer:

(C) 32967

Explanation:

The numbers lying between 200 and 800, which are divisible by 9 are,

207, 216, 225, .... 792

Here, First term is, a = 207

and Last term is = 792

difference is, d = 9

Let the total number of terms of the A.P. is equal to n.

and we know the formula of A.P. series

last term = a + (n - 1) d

792 = 207 + (n - 1) 9

9 (n - 1) = 585

9n = 594

n = 66

Sum of 66  = 66 / 2 (207 + 792)

= 33(999)

= 32967

Thus, the required sum is 32967.

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