Math, asked by srikalyani247407, 7 hours ago

66. The sum of six terms of an AP is 345. The difference between the first and last termis 55. Then the numbers are 11 1) 30, 41, 52, 63, 74,85 2) 1, 2, 3, 4, 5,6 3)2, 4, 6, 8, 10, 12 4) none​

Answers

Answered by jnanajyothits
0

Answer:

Let the terms be a,a+d,a+2d,a+3d,a+4d,a+5d a , a + d , a + 2 d , a + 3 d , a + 4 d , a + 5 d . Hence, the terms are 30,41,52,63,74,85 30 , 41 , 52 , 63 , 74 , 85 .

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