66. The sum of six terms of an AP is 345. The difference between the first and last termis 55. Then the numbers are 11 1) 30, 41, 52, 63, 74,85 2) 1, 2, 3, 4, 5,6 3)2, 4, 6, 8, 10, 12 4) none
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Let the terms be a,a+d,a+2d,a+3d,a+4d,a+5d a , a + d , a + 2 d , a + 3 d , a + 4 d , a + 5 d . Hence, the terms are 30,41,52,63,74,85 30 , 41 , 52 , 63 , 74 , 85 .
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