Question

66. Under similar conditions, 390cm of gas A of
molar mass M and 130cm of gas B of molar
mass M, diffuesed out through a porous
container in the time ratio of 2 : 1. The ratio
of Mto M.is​

Answer 1

Answer:

4:9

Explanation:

As you know r=$\frac{1}{\sqrt{M} }$

$\frac{t_{1} }{t_{2} }$ X $\frac{V_{2} }{V_{1} }$ = $\sqrt{\frac{M_{1} }{M_{2} } }$

$\frac{t^{2} _{1} }{t^{2} _{2} }$ X $\frac{V^{2} _{2} }{V^{2} _{1} }$ = $\frac{M_{1} }{M_{2} }$

= 4:9