Question

66. Which of the following divides the line joining the points P(-4, 2) and Q(8, 3) in the ratio 2 : 5?
(a) 7x + 4 = 0
(b) 7y - 16 = 0

(1) Neither (a) nor (b)
(2) Both (a) and (b)
(4) Only (a)
(3) Only (b)​

Answer 1

Answer:

(2)Both(a) and (b)

Step-by-step explanation:

We are given that a line joining the points P(-4,2) and Q(8,3) and divide in the ratio 2:5.

Let the point R(x,y) divide the line formed by joining P and Q.

The coordinates of R is given by section formula

$x=\frac{m_1x_2+m_2x_1}{m_1+m_2},y=\frac{m_1y_2+m_2y_1}{m_1+m_2}$

Substitute the values then we get

$x=\frac{2 (8)+5(-4)}{2+5}=\frac{-4}{7}$

$7x=-4$

$7x+4=0$

$y=\frac{2(3)+5(2)}{7}=\frac{16}{7}$

$7y=16$

$7y-16=0$

Answer:(2)Both(a) and (b)