Question

67.2 litres of hydrogen combines with 44.8
litres of nitrogen to form ammonia under
specific conditions as :
N2(g) + 3H2(g) + 2NH3(g)
Calculate the volume of ammonia produced.
What is the other substance, if any, that
remains in the resultant mixture ?
​

Answer 1

Answer:

As seen in the reaction 1 vol. of nitrogen combines with 3 volumes of hydrogen to give 2 volumes of ammonia. If 1 vol. of N^2 gives 2 vol. of NH3 Then, 44.8 L of N2 gives = 2×44.8 =89.6L.

Explanation:

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