Question

67. A conductor moving with a speed of 20 m/s in the direction perpendicular to the
direction of magnetic field of induction 0-5 T, induces an EMF of 5 V. The length of the
conductor is
ఒక వాహకము 0-5 T ప్రేరణ కలిగిన అయస్కాంత క్షేత్రానికి లంబదిశలో 20 m/s వేగంతో ప్రయాణిస్తూ, 5 V ప్రేరిత విద్యుతచ్ఛాలక బలాన్ని
కలుగచేసింది. ఆ వాహకం యొక్క పొడవు
(1) 1 m
(2) 5 m
(3) 50m
(4) 0-5 m​

Answer 1

Step-by-step explanation:

Given A conductor moving with a speed of 20 m/s in the direction perpendicular to the direction of magnetic field of induction 0-5 T, induces an EMF of 5 V. The length of the  conductor is

• Now induced emf = Blv sin theta where theta is the angle made between velocity of conductor and magnetic field. If v is perpendicular to B, then angle between l and B is theta. . If l is perpendicular to B, then angle between v and B is theta.
• Now velocity of conductor or speed v = 20 m/s
• Also magnetic field B = 0.5 T
• Induced or motional emf = 5V
• We need to find the length of the conductor.
• So induced emf = Blv sin theta  
•             5 = 0.5 x l x 20 sin 90
•             5 = 0.5 x 1 x 20 (1)
•              5 = 10 l
•       Or l = 5/10
•   Or l = ½  
•   Or l = 0.5 m

Reference link will be

https://brainly.in/question/8628128

https://brainly.in/question/24151471

Answer 2

Answer:

l=0.5m hope it helps you