Question

67. The molarity of solution obtained by dissolving 0.01 moles of NaCL in 500ml of solutions is
a) 001M
b) 0.005 M
C) 0.02 M
d) 0.1 M
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Answer 1

Given :-

Number of moles = 0.01 moles

Volume of solution = 500 ml

To Find :-

Molarity

Solution :-

We know :-

Molarity (M) :- It is defined as number of moles of the solute in 1 litre of the solution.

$\sf Molarity = \dfrac{Number \: of \: moles }{Volume \: in \: liters}$

Here :-

Numbers of moles = 0.01 moles

Volume = 500 ml

Substitute the values :-

$: \implies \sf Molarity = \dfrac{0.01 \times 1000}{500}$

$: \implies \sf Molarity = 0.01 \times 2$

$: \implies \bf Molarity = 0.02$

Molarity of the solution = 0.02M

Correct option is (C).

Answer 2

Given :-

The molarity of solution obtained by dissolving 0.01 moles of NaCL in 500ml

To Find :-

Molarity

Solution :-

We know that

Molarity of any solution = Moles of the solute/Volume

Molarity = 0.01/500 × 1000

Molarity = 0.00002 × 1000

Molarity = 0.02 M

Option C is correct