Math, asked by deepukumbagiri, 8 months ago


68/21 = x+1/y+1/z then find x,y,z if x,y,z £N​

Answers

Answered by ILLUSTRIOUS27
3

Step-by-step explanation:

68/21=x+1/y+1

68(x+1)=21(y+1).......cross multiplication

68x+68=21y+21

68x-21y=-47

x=47+21y/x

this is half questions if you want full question pls tell me

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