Question

(68-a)(68-b)(68-c)(68-d)(68-e) = 725 , a+b+c+d?

Answer 1

725 has maximum of 4 factors excluding 7:25 itself therefore we can write 725 as a product of 2 fives and 1 ones and 1 twenty nine. So the first factor can be written as 68 - 63 and the second factor can be written the same 68 minus 63 and the third factor can be written as 68 - 39 and fourth factor can be written as 68 - 67.

Therefore you can write it as:

(68-a)(68-b)(68-c)(68-d)(68-e) = 725 = (5)(5)(29)(1)

or, or a=b=63; c=39; d=67.