Question

68. A particle moves with a velocity of 6î - 49 + 3k m/s
under the application of a constant force
F = 20 + 159 - 5k N. What is the instantaneous
power applied to the particle ?
(a) 25 J/S
(b) 35 J/s
(c) 45 J/s
(d) 55 J/s​

Answer 1

Answer:

P=

F .

v

=20×6+15×(−4)+(−5)×3

=120−60−15=120−75=45 J/s