Question

68.
Box 1 contains 8 tickets numbered 1 to 8 and Box 2 contains 8 tickets numbered 2 to 9.
One ticket is selected at random from each box. What is the probability that the sum of
the number on ticket is 9?​

Answer 1

Answer:

7/16

Step-by-step explanation:

probability in case 1 is 1/8

probability in case 2is 1/8

:

Answer 2

The probability that the sum of

the number on ticket is 9 is $\frac{7}{16}$.

Step-by-step explanation:

Given:

• Box 1 contains 8 tickets numbered 1 to 8.
• Box 2 contains 8 tickets numbered 2 to 9.
• One ticket is selected at random from each box.

So, for sum of the numbers on ticket to be 9 there are 7 combinations.

(1,8),(2,7),(3,6),(4,5),(5,4),(6,3) & (7,2) are 7 combinations for which we get sum 9.

The total probability that the sum of the numbers on ticket be 9 is

$= > p = \frac{1}{8} \times \frac{1}{8 } + \frac{1}{8} \times \frac{1}{8 } + \frac{1}{8} \times \frac{1}{8 } + \frac{1}{8} \times \frac{1}{8 } + \frac{1}{8} \times \frac{1}{8 } + \frac{1}{8} \times \frac{1}{8 } + \frac{1}{8} \times \frac{1}{8 }$

$= > p = \frac{7}{16}$