Math, asked by shubhamraja1011, 11 months ago

68. (cosec 0 - sec 0) (cot 0 - tano) =(cosec 0 + sec 0) (sec 0 cosec 0 - 2)

Answers

Answered by jobyachu924

1

Answer:

cosec 0= infi

sec0=1

cot0=infi

tan0=0

by applying this to the prob, we'll get LHS =RHS

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