68. In the given figure, triangle ABC is drawn such
that AB is tangent to a circle at A whose radius
is 10 cm and BC passes through centre of the
circle. Point C lies on the circle. If BC = 36 cm
and AB = 24cm, then what is the area (in cm) of
triangle ABC?
दी गई आकृति में, त्रिभुज ABC को इस प्रकार बनाया गया है कि
AB एक 10 सेमी. त्रिज्या वाले वृत्त को A पर स्पर्श रेखा है तथा
BC वृत्त के केंद्र से होकर गुजरती है। बिंदु C वृत्त पर स्थित है।
यदि BC = 36 सेमी. तथा AB = 24 सेमी. हो, तो त्रिभुज ABC
का क्षेत्रफल (से.मी.2 में) क्या है?
(1) 134.5
(3) 168
(2) 148
(4) 180
Answers
Answered by
3
Area of Δ ABC = 168 cm²
Step-by-step explanation:
AB = 24cm
BC = 36 cm
Radius = 10 cm
=> OB = BC - OC
=> OB = 36 - 10
=> OB = 26
Sin∠B = OA/OB
=> Sin∠B = 10 / 26
Area of Δ ABC = (AB * BC * Sin∠B) /2
= ( 24 * 36 * (10/26))/2
= 2160/13
= 166.15 cm²
Closest answer is 168 cm²
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