Math, asked by arpitasona223, 9 months ago

68^n +1 is exactly divisible by 23 where n is?​

Answers

Answered by asahilthakur
1

Answer:

n = 1

Explanation:

68ⁿ + 1

By putting 1 at place of n, we get

68¹ + 1

= 68 + 1

= 69

69 is exactly divisible by 23.

Answered by piyushnehra2006
0

Answer:

The value of n is 1

Step-by-step explanation:

If the value of n is 1

68*1=68

68+1=69

It is exactly divisible by 23 in 3 times

23*3=69

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