Math, asked by sreeyasatish262, 2 months ago

68)PQRS is a trapezium, in which SRII PQ, and SR is 7cm longer than PQ. If
the area of the trapezium is 186 sq cm and the hight is 12 cm find the lengths of parallel sides.​

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Answered by sanjanaagrahari611
0

Answer:

PQRS is an isosceles trapezium. l(PQ)=7 cm. segment PM perpendicular to segment SR, l(SM)=3 cm, Distance between two parallel sides is 4 cm, Find the area of PQRS.

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Length of PQ=7 cm

Length of PM= distance between two parallel sides =4 cm

Length of SM=3cm

Length of SR=SM+MN+NR

because PQRS is isosceles trapezium,

so, SR=NR=3cm and MN=PQ=7cm

so, Length of SR=3cm +7cm +3cm =13cm

Now, area of PQRS=

2

1

(PQ+SR)×PM

=

2

1

(7+13)×4

=20×2=40sq.cm

Answer 40

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