Question

68. The ages of A and B three years ago were x and y +2 years. Therefore the sum of their ages four years hence will be (A) x + y - 12 (B) x + y + 12 (C) x + y + 16 (D) x + y - 16​

Answer 1

Answer:

The ages of A and B three years ago were ' x ' and 'y + 2 ' years , therefore ...

Answer 2

Answer:

Age of A 3 yrs ago : x years

So, present age of A is : x+3 yrs

Age of B 3 years ago : y+2 years

So, present age of B is : y+5

Age of A 4 years hence(after) : x+3+4 =x+7

Age of B 4 years hence : y+5+4 = y+9

So, Sum of ages of A and B after 4 yrs : (x+7) + (y+9) = x+y+16

Hence, answer to this question is x+y+16

Step-by-step explanation: