Question

68nm of dna contains 30 adenine calculate the hydrogen bond

Answer 1

hey! Here is the your Answer

As length ofDNA is 68 NM ,The distance between two base pairs = 0.34 nm
As one complete spiral / 360 degree round of DNA contains 10 bp,, ,the length of 1 spiral is equals to 10*0.34 nm = 3.4 nm
let's calculate total no. of DNA spirals 68 nm / 3.4 nm = 20 spirals. for 1 spiral ➡10 bp then for 20 spirals ➡ 20* 10=200 bp = 400 nucleotides. Out of 400 ,, , 30 are adenine hence thymine should 30 in no. 30+30=60 ................400-60 = 340. (guanine + cytosine)
340/2 = 170 guanine. and 170 cytosine.

# During calculating the total hydrogen bonds consider only one strand of DNA and only one type of nuclieotides forming pair with complementary base. bcoz they both together forms hydrogen bonds. adenine are 30 hence will form 30*2 =60 hydrogen bonds with thymine . cytosine are 170 and will form 170*3=510 hydrogen bonds with guanine . so total no. of hydrogen bonds are 60+ 510 = 570 .....
hence ANSWER is 570 hydrogen bonds. I hope u got it, and this is correct answer.