Question

ᴅᴇᴛᴇʀᴍɪɴᴇ ᴇᴍᴩᴇʀɪᴄᴀʟ ꜰᴏʀᴍᴜʟᴀ ᴏꜰ ᴀɴ ɪʀᴏɴ ᴡʜɪᴄʜ ʜᴀꜱ 69.9% ɪʀᴏɴ ᴀɴᴅ 0.1% ᴏxyɢᴇɴ ʙy ᴍᴀꜱꜱ .ꜰɪɴᴅ ᴍᴏʟᴇᴄᴜʟᴀʀ ꜰᴏʀᴍᴜʟᴀ ᴀʟꜱᴏ​

Answer 1

Answer:

myself aatiya

nickname suhana

from Mumbai

and your

Answer 2

The iron oxide has 69.9% iron and 30.1% dioxygen by mass.

Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.

The number of moles of iron present in 100 g of iron oxide are

55.8

69.9

=1.25.

The number of moles of dioxygen present in 100 g of iron oxide are

32

30.1

=0.94.

The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is

1.25

2×0.94

=1.5:1=3:2.

Hence, the formula of the iron oxide is Fe2o3

bhot mehnet lagi hai bhai ise solve Karne ke liye