Question

(6a+1)/3 + 1=(a-3)/6. WHAT IS THE VALUE OF a? ​

Answer 1

Answer:

hey mate here is your answer

Answer 2

Answer:

a= -1

Step-by-step explanation:

STEP 1- Find common denominator

= $\frac{6a+1}{3}+1= \frac{(a-3)}{6}$

= $\frac{6a+1}{3} +\frac{3}{3} = \frac{(a-3)}{6}$

STEP 2- Combine fractions with common denominator

= $\frac{6a+1}{3} +\frac{3}{3} = \frac{(a-3)}{6}$

= $\frac{6a+1+3}{3} = \frac{(a-3)}{6}$

STEP 3- Add the numbers

= $\frac{6a+1+3}{3} = \frac{(a-3)}{6}$

= $\frac{6a+4}{3} = \frac{a-3}{6}$

STEP 4- Multiply all terms by the same value to eliminate fraction denominators

= $\frac{6a+4}{3} = \frac{a-3}{6}$

= $6\frac{(6a+4}{3)} = 6\frac{a-3}{6}$

= $2(6a+4)= a-3$

= $12a+8=a-3$

= $12a+8-8= a-3-8$

= $12a= a-3-8$

= $12a=a-11$

= $12a-a=a-11-a$

= $11a= a-11-a$

= $11a=-11$

= $\frac{11a}{11} = \frac{-11}{11}$

$a=\frac{-11}{11}$

$a=-1$