6a^2 + 17ab -3b^2 factorise by middle term splitting
Answers
Answered by
22
Answer:
Given :-
- 6a² + 17ab - 3b²
To Find :-
- Factorise by middle term splitting ?
Solution :-
Given Equation :
EXTRA INFORMATION :-
❒ Quadratic Equations With One Variable :
The general form of this type of equation is ax² + bx + c .
[Note :
If a = 0, then the equation becomes to a linear equation.
If b = 0, then the roots of the equation becomes equal but opposite in sign.
If c = 0, then one of the roots is zero.
❒ Nature Of Roots :
b² - 4ac is the discriminant of the equation. There are two roots.
◆ When b² - 4ac = 0, then the roots are real & equal.
◆ When b² - 4ac > 0, then the roots are imaginary & unequal.
◆ When b² - 4ac < 0, then there will be no real roots.
Answered by
1
Answer:
6a² + 17ab - b²
= (6a - b)(a + 3b)
Step-by-step explanation:
6a² + 17ab - 3b²
= 6a² + 18ab - 1ab - 3b²
= 6a (a + 3b) - b (a + 3b)
= (6a - b)(a + 3b)
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