Math, asked by jyotishmanarya2, 13 days ago

6a^2 + 17ab -3b^2 factorise by middle term splitting

Answers

Answered by StarFighter
22

Answer:

Given :-

  • 6a² + 17ab - 3b²

To Find :-

  • Factorise by middle term splitting ?

Solution :-

Given Equation :

\implies \bf 6a^2 + 17ab - 3b^2\\

\implies \sf 6a^2 + (18 - 1)ab - 3b^2\\

\implies \sf 6a^2 + 18ab - ab - 3b^2\: \: \small \bigg\{ \bf By\: Splitting\: The\: Middle-Term\bigg\}\\

\implies \sf 6a(a + 3b) - b(a + 3b)\\

\implies \sf\bold{\underline{(a + 3b) (6a - b)}}\\

\\

EXTRA INFORMATION :-

❒ Quadratic Equations With One Variable :

The general form of this type of equation is ax² + bx + c .

[Note :

If a = 0, then the equation becomes to a linear equation.

If b = 0, then the roots of the equation becomes equal but opposite in sign.

If c = 0, then one of the roots is zero.

❒ Nature Of Roots :

b² - 4ac is the discriminant of the equation. There are two roots.

◆ When b² - 4ac = 0, then the roots are real & equal.

◆ When b² - 4ac > 0, then the roots are imaginary & unequal.

◆ When b² - 4ac < 0, then there will be no real roots.

Answered by sradhadileep191sa49
1

Answer:

6a² + 17ab - b²

= (6a - b)(a + 3b)

Step-by-step explanation:

6a² + 17ab - 3b²

= 6a² + 18ab - 1ab - 3b²

= 6a (a + 3b) - b (a + 3b)

= (6a - b)(a + 3b)

Similar questions