Question

(6a^2-7a-5) ÷(2a+1)​

Answer 1

$\large\sf\underline{Given}$

• $\sf\:\frac{6a^{2}-7a-5}{2a+1}$

$\large\sf\underline{Solution :-}$

$\sf\:\frac{6a^{2}-7a-5}{2a+1}$

$\sf↦\:\frac{6a^{2}-(10-3)a-5}{2a+1}$

$\sf↦\:\frac{6a^{2}-10a+3a-5}{2a+1}$

$\sf↦\:\frac{2a(3a-5) +1(3a-5)}{2a+1}$

$\sf↦\:\frac{(2a+1)(3a-5)}{2a+1}$

$\tt\purple{↦\:3a-5}$

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(2a+1) in numerator and denominator gets cancelled !

• Thnku ❣

Answer 2

Refer to the attached image.