Question

6a+5b-0-a²-b²,Write the number of terms in given polynomial.

Answer 1

Hey there!

6a + 5b - 0 - a^2 - b^2

Here, 5 terms are given i.e 4 with variables and 1 constant.

With Variables = 6a ,5b , a^2 , b^2

Constant = 0

Hope It helps You!

Answer 2

Hey!

Here's your answer ^^

Given polynomial -.

6a + 5b - 0 - a² - b²

Terms = 5,
Those are = 6a, 5b, 0 (more likely to be considered as a constant), -a², -b²

Hope it helps!