(6a-5b+3c)^2 expand it with identity
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Here is your answer..
(6a-5b+3c)²
= (6a+(-5b)+3c)²
USING IDENTITY : (a+b+c)²
= a²+b²+c²+2ab+2bc+2bc.
Where, a=6a, b=-5b, c=3c
= (6a)²+(-5b)²+(3c)²+2(6a)(-5b)+2(-5b)(3c)
+2(6a)(3c)
= 36a²+25b²+9c²-60xb-30bc+54ac
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