Math, asked by aishwaryaksrs, 1 month ago

(6a-5b+3c)^2 expand it with identity ​

Answers

Answered by shuklatwisha567
2

Answer:

Sorry I don't know

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Answered by Cuteprincess4188
3

Here is your answer..

(6a-5b+3c)²

= (6a+(-5b)+3c)²

USING IDENTITY : (a+b+c)²

= a²+b²+c²+2ab+2bc+2bc.

Where, a=6a, b=-5b, c=3c

= (6a)²+(-5b)²+(3c)²+2(6a)(-5b)+2(-5b)(3c)

+2(6a)(3c)

= 36a²+25b²+9c²-60xb-30bc+54ac

Thank u

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