Question

(6a-5b+3c) whole square ​

Answer 1

Pre Requisite Knowledge for this Question

(a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca

(6a - 5b + 3c)²

Applying the (a+b+c)² identity [given above]

= (6a)² + (-5b)² + (3c)²

+ 2(6a)(-5b) + 2(-5b)(3c) + 2(3c)(6a)

= 36a² + 25b² + 9c² - 60ab - 30bc + 36ca

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