6a2 - 3a2b - bc2 + 2c2
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nswered May 21, 2019 by muskan15 (-3,446 points)
6a2 – 3a2b – bc2 + 2c2
= 6a2 – 3a2b + 2c2 – bc2 (By grouping)
= 3a2 (2 –b) + c2 (2 – b)
= (2 – b) (3a2 + c2)
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