6a² + a-2....Factorise step by step
Answers
Answered by
1
6a^2+a-2
Product of numerical coefficients of first and last term=(-12)
We have to arrange the middle term in such a way that product of its numerical coefficients is (-12)
=6a^2+4a-3a-2
=2a(3a+12)-1(3a+12)
=(3a+12)(2a-1)
Similar questions