Question

6a²x²-7abx-3b²=0. Find the roots

Answer 1

Answer:

thank you my lovely guys

Answer 2

Here ,Applying Quadratic Formula ,

b = b2-4ac

= (-7ab)^2 -4 (6a^2)(-3b^2)

= 49a^2b^2 + 72a^2b^2

= 121a^2b^2

Now, x = (7ab +- root 121a^2b^2)÷2(6a²)

= (7ab +- 11ab ) ÷ 12a²

= ( 20ab)/12a² or 4ab/12a²

= 5/3ab or - 1/3ab .

So, these are its roots .

BRAINLIEST PLS

100% CORRRCT