Question

6a³- 5b²+ 2c²- 3a²bc. if a= 1, b= 2, c= -1. Please show with process. Class Vi type Answer I need​

Answer 1

Answer:

-6

Step-by-step explanation:

6a^3 - 5b^2 + 2c^2 - 3a^2bc

a = 1 , b = 2 , c = -1

=. 6(1)^3 - 5(2)^2 + 2(-1)^2 - 3(1)^2(2)(-1)

= 6 × 1 - 5 × 4 + 2 × 1 - 3 × (-2)

= 6 - 20 + 2 + 6

= -14 + 8

= -6

I Hope this Will help you..

plz follow

Answer 2

Answer:

See the attachment.......