Question

6a3b is divisible by 9,so find the value of a and b?

Answer 1

If 6a3b is divisible by 9, then 6 + a + 3 + b = 9 + a + b should be a multiple of 9.

∴ The possible values of (a,b) are:

(0,0),(0,9),(1,8),(2,7),(3,6),(4,5),(5,4),(6,3),(7,2),(8,1),(9,0),(9,9)

Hope it helps :)

Answer 2

Answer

MC+BC=TMKC=IMP=BTMKC