Question

6ab×4=2a72


Please tell fast​

Answer 1

Answer:

Correct option is

D

50 amu

A

B

C

AB

2

C

3

Molecular mass

60 amu

80 amu

Number of moles present

0.1

1

0.036

Number of moles reacted

0.012

0.024

0.036

Mass reacted (g)

0.72

2.88

4.8

In this reaction, C is the limiting reagent.

The mass of B reacted =4.8−2.88−0.72=1.2 g.

Thus, 1.2 g of B corresponds to 0.024 moles.

The molar mass of B is

0.024

1.2

=50 amu.