Math, asked by sunilchauhan31382, 1 year ago

6ab - b^ + 12ac - 2bc

Answers

Answered by AtomixEnergy5

24

Answer:

6ab - b² + 12ac - 2bc

= 6ab + 12ac - b² - 2bc

= 6a( b + 2c ) - b( b + 2c )

= ( b + 2c ) ( 6a - b )

I hope this helps you.

: )

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