Question

6abc - 2a2c + 9b2-3ab by (2ac + 3b)​

Answer 1

Step-by-step explanation:

a3 + b^{3}b3 + 8c^{3}8c3 - 6abc

= (a)^{3}(a)3 + b^{3}b3 + (2c)^{3}(2c)3 - 3(a * b * 2c)

= ( a + b + c) {a^{2}a2 + b^{2}b2 + (2c)^{2}(2c)2 - ab - 2bc - 2ca}

= (a + b+ c) ( a^{2}a2 + b^{2}b2 + 4c^{2}4c2 - ab - 2bc - 2ca)

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