Math, asked by p098, 27 days ago

(∆+6b)² = 25a² + 60 ab + 36b² Which of these given value of ∆ will make the above equation true? *​

Answers

Answered by sujeetsahani8745
1

25a²+60ab+36b²

(a+b)²=a²+2ab+b²

(5a+6b)² =25a²+60ab+36b²

Answered by kanvi14
2

(5a+6b)² = 25a² + 60 ab + 36b²

Step-by-step explanation:

Formula - (a+b)² = a²+2ab+b²

Given - (∆+6b²) = 25a²+60ab+36b²

Now,

(∆+6b²) = (∆)²+2×∆×6b+(6b)²

(since we know that the square root of 25 is 5)

therefore,

(5a+6b)² = (5a)²+2(5a)(6b)+(6b)²

(5a+6b)² = 25a² + 60 ab + 36b²

Hope this helps you!!

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