(∆+6b)² = 25a² + 60 ab + 36b² Which of these given value of ∆ will make the above equation true? *
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25a²+60ab+36b²
(a+b)²=a²+2ab+b²
(5a+6b)² =25a²+60ab+36b²
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(5a+6b)² = 25a² + 60 ab + 36b²
Step-by-step explanation:
Formula - (a+b)² = a²+2ab+b²
Given - (∆+6b²) = 25a²+60ab+36b²
Now,
(∆+6b²) = (∆)²+2×∆×6b+(6b)²
(since we know that the square root of 25 is 5)
therefore,
(5a+6b)² = (5a)²+2(5a)(6b)+(6b)²
(5a+6b)² = 25a² + 60 ab + 36b²
Hope this helps you!!
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