Chemistry, asked by Asadhya, 5 months ago

6dm3 of dry gas at temperature of 27 degree Celsius and pressure of 700 mm Hg. find the volume of gas at S.T.P.Give full details. Don't give only ans give full details.​

Answers

Answered by s02371joshuaprince47
0

Answer:

P=  

V

n

​  

RT=  

V

m

​  

×  

M

RT

​  

=  

M

dRT

​  

 

or d=  

RT

PM

​  

 or d∝  

T

P

​  

 

d  

2

​  

 

d  

1

​  

 

​  

=  

P  

2

​  

 

P  

1

​  

 

​  

×  

T  

1

​  

 

T  

2

​  

 

​  

 or  

d  

2

​  

=  

P  

1

​  

×T  

2

​  

 

d  

1

​  

×P  

2

​  

×T  

1

​  

 

​  

 

d  

2

​  

=  

2×273

5.46×1×300

​  

=3.0 g dm  

−3

Answered by assetmanyaira
0

Answer:5.03l

Explanation: the first step is to identify the the given components, V=6dm3

T=27°

P=700mmHg

Step2, identify the possible law to apply, and in this case its Boyles' which states that volume is inversely proportional to pressure at constant temperature.

Therefore, P1. V1/T1 =P2. V2/T2

Step3, note the units, 6dm3 converted to litres remains 6l, and for the temperature in C we add 273 to 27C to get 300K

Step4, we then substitute for our equation hence, 760.V1/273=700.6/300

V1=5.03l

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