Chemistry, asked by arathyanil8089, 21 hours ago

6g C is burnt completely in excess of air. The volume CO₂ formed at STP is​

Answers

Answered by WintaeBearTATA
1

Answer:

C+02-->CO2

12g Co2 reacts with 32 g 02 to produce 44gCO2

6g will react with 16g 02 to give 22g CO2

44gCO2 contains 22.4L 22g CO2 contains 11.2L volume at STP

22.4L contains 6.022* 10^23 So 11.2L will contain 6.022 * 10^23/2=3.011*10^23 molecules of CO2

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