Question

6g H2 react with 8g oxygen to form water. after the completion of the reaction what is the limiting reagent

Answer 1

2H2+O2→2H2O10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol

Explanation:

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water. 2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water. Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

Answer 2

Answer:

O2

Explanation:

2H2+O2→2H2O

10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol  10 g = 5 mol  

64 of oxygen  (molar mass 32 g/mol) = 32 g/mol  64 g = 2 mol  

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.