6g of hydrogen at 1.5 atm and 273c occupies a volume of
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Answer:
volume =89.544L
Explanation:
Assuming hydrogen is an ideal gas :
The ideal gas eq.=PV=nRT
where P is pressure, V is volume , n is no. of moles, R is gas constant , T is temperature.
Molecular mass of hydrogen gas =2g/mol
no. of moles = mass/molecular mass
=> n= 6/2= 3
also,
Temperature in Kelvin= temperature of Celsius+273
=>T= 273+273= 546K
put the value in ideal gas eq :
PV=nRT
1.5×V= 3×0.082×546. (R=0.082 atmL/mol/K)
V = 89.544L
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